Question

If ABCD is dilatedby a factor of 1/2, thecoordinate of B' would be:B'= ([?],[ ])

Answer 1

First find the B coordinate, which is:

`B=(-2,2)`

Now multiply by a scalar of 1/2

`B^(\prime)=(1)/(2)(-2,2)=(((1)/(2)*-2),((1)/(2)*2))`
`B^(\prime)=(-1,1)`