Question

A car traveling at 11.6 meters per second crashes into a barrier and stops in 0.287 meters. How many times the weight of the child is this force? Answer must be in 3 significant digits.

Answer 1

The weight of child can be given as,

`w=mg`

Substitute the known values,

`\begin{gathered} w=(21.2kg)(9.8m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =207.76\text{ N} \end{gathered}`

Divide the value of force with the weight.

`\begin{gathered} (F)/(w)=\frac{4970\text{ N}}{207.76\text{ N}} \\ =23.9 \end{gathered}`

Thus, the force is 23.9 times the weight of child.