First let's create the sample space of the experiment
let S denotes the sport car , T denote the pick up truck and R denotes the grandma ride.
Then the possible combinations will be

Now let E deontes the event of getting grandma ride and F denotes the event of getting new vehicle
Then

So

So the probabilty of getting a grandma ride and a vehicle in new condition is 1/12
Now let A denote the event of getting a sports car and B denote the event of getting a vehicle in fair condition so

So

So the probabilty of getting a sports car or a vehicle in fair condition is 6/12