Line 1: 2y = 5x +4
Line 2: y= 3x-2
Line 3: 10x+4y=6
First, express each line in slope-intercept form: and find the slope of each line:
y= mx+b
Where:
m= slope
Solve for y foe each line,
Line 1
2y=5x+4
y= 5/2x +2
m= 5/2
Line 2
y=2/5x-2
m= 2/5
Line 3:
10x+4y=6
4y=-10x+6
y= -5/2x+3/2
m= -5/2
Lines to be parallel must have the same slopes. none have
Lines to be perpendicular must have negative reciprocal slopes.
Lines 2 and 3 have negative reciprocal slopes (-5/2) and (5/2)
Lines 2 and 3 are perpendicular
The rest pairs are neither