Answer:
1/(xy²)
Step-by-step explanation:
The given expression is
![(x^(-4)y^(-2)z^7)/(x^(-3)z^7)](https://img.qammunity.org/2023/formulas/mathematics/college/a2gsfpei7xndmo8bssnaw3ue5zorlow38o.png)
To simplify the expression, we will use the following properties
![\begin{gathered} (x^a)/(x^b)=x^(a-b) \\ x^(-a)=(1)/(x^a) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v1xgmencp2b8q5c6kqjgfmonpvq0szmgl7.png)
So, we need to apply the first property for x and z to get:
![\begin{gathered} (x^(-4)y^(-2)z^7)/(x^(-3)z^7)=x^(-4-(-3))y^(-2)z^(7-7)^{} \\ ^{}=x^(-4+3)y^(-2)z^0 \\ ^{}=x^(-1)y^(-2)\cdot1 \\ =x^(-1)y^(-2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/86eatucjz8ek7oub72ral5qfdwvh6n1zhy.png)
Because any number to the power of 0 is equal to 1. Then, apply the second property to get
![(1)/(x^1y^2)=(1)/(xy^2)](https://img.qammunity.org/2023/formulas/mathematics/college/idixzdqh5lrw95959wbv65icfhklpfsuky.png)
Therefore, the answer is 1/(xy²)