If m H=68°, what is HI to the nearest tenth? Show your work.

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asked Dec 20, 2023 77.9k views

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Garajo · Answer 1 · 2023-12-26T14:44:38+0000

Given data:

The given angle is ∠H= 68°.

The given length is GH=2 cm.

The expression for cos(H) is,

$\begin{gathered} \text{cos(H)}=(GH)/(HI) \\ \cos (68^(\circ))=\frac{2\operatorname{cm}}{HI} \\ HI=\frac{\text{2 cm}}{\cos (68^(\circ))} \\ =5.3389\text{ cm} \\ \approx5.34\text{ cm} \end{gathered}$

Thus, the value of HI is 5.34 cm.

If m H=68°, what is HI to the nearest tenth? Show your work.

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