Question

A of each figure? 14 1 in. 15 1 in. 1 in. 1 in. 3 . о q 6 B B С in.2 Area = 2 in. Area = 6

Answer 1

In the given question 14,

There are 4 squares and 4 right triangles in the diagram.

The area of right triangle is determined by,

`A_1=(1)/(2)* b* h`

Here , b is the base of the right triangle and h is the height of the triangle.

The area of sqaure is ,

`A_2=(side)^2`

From the diagram, the side of square is 1 inch and base and height is also inch.

Substitute the values in the formula of triangle ,

`A_1=(1)/(2)*1*1`
`A_1=0.5in^2`

The area of 4 right triangles is ,

`A^(\prime)=4*0.5=2in^2_{}`

Substitute the value in the formula of square,

`A_2=(1)^2`

The area of 4 square is,

`A^(\doubleprime)=4*1=4in^2`

The area of the figure obtained is ,

The sum of area of 4 square and area of 4 triangle.

`A=2+4=6in^2\text{.}`