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Find the center and radius of the circle x^2 + 6x + y^2 =12

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C(-3,0) and the Radius is R =√21

1) Let's consider this formula x² + 6x +y² = 12. Reminding that the formula of the circle is given by

(x-a)² +(y-b)² =r² Let a, and b the coordinates of the Center of the Circle)

2) So we can write

x² +6x +y² =12 Rewriting it grouping

(x² + 6x) +y²=12 Complete the square, add 9 to both sides

(x²+3x+9) +y²= 12+9

(x+3)²+y²=21

3) So we can state that the Center and the Radius are, comparing it to the General Formula:

C(-3,0) and the Radius is R =√21

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