Question

a 5.4kg ball is dropped from a cliff and it accelerates downward due to the force of gravity. what is the ball's downward velocity after 3 seconds of freefall? (assuming we ignore air resistance)

Answer 1

velocity = 29.4 m/s

Step-by-step explanation:

We have been told to calculate the velocity of a ball after 3 seconds of freefall. To do this, we can use the following formula:

`\boxed{v = u + at}`,

where:

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time of freefall

In this case, u = 0 m/s, because the ball is initially stationary before it is released. Also, a = 9.81 m/s² because the ball is falling while inside the Earth, where the acceleration of freefall is 9.81 m/s².

Using the above information along with the formula, we can calculate the velocity of the ball after 3 seconds of freefall:

v = 0 m/s + (9.81 m/s² × 3 s)

= 29.4 m/s