Question

Find the surface area of a square pyramid with side length 2 km and slant height 4 km

Answer 1

The diagram can be drawn as,

The surface area of the base is

`\begin{gathered} BA=(2km)^2 \\ ^{}=4\text{ sq. km} \end{gathered}`

The lateral surface area can be determined as,

`\begin{gathered} \text{LSA}=(1)/(2)* Perimeter\text{ of base}* slant\text{ height} \\ =(1)/(2)*(4*2\text{ km)}*4\text{ km} \\ =16\text{ sq km.} \end{gathered}`

The total surface area can be determined as,

`\begin{gathered} \text{TSA}=BA+\text{LSA} \\ =4\text{ sq km+16 sq km} \\ =20\text{ sq km.} \end{gathered}`

Thus, the total surface area is 20 sq km.