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Find the surface area of a square pyramid with side length 2 km and slant height 4 km

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The diagram can be drawn as,

The surface area of the base is


\begin{gathered} BA=(2km)^2 \\ ^{}=4\text{ sq. km} \end{gathered}

The lateral surface area can be determined as,


\begin{gathered} \text{LSA}=(1)/(2)* Perimeter\text{ of base}* slant\text{ height} \\ =(1)/(2)*(4*2\text{ km)}*4\text{ km} \\ =16\text{ sq km.} \end{gathered}

The total surface area can be determined as,


\begin{gathered} \text{TSA}=BA+\text{LSA} \\ =4\text{ sq km+16 sq km} \\ =20\text{ sq km.} \end{gathered}

Thus, the total surface area is 20 sq km.

Find the surface area of a square pyramid with side length 2 km and slant height 4 km-example-1
User Arsen Khachaturyan
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