Question

Can you please help me also this is homework I do online schooling so it looks weird

Answer 1

Given data:

* The mass of the truck is m_1 = 3000 kg.

* The mass of the parked car is m_2 = 1000 kg.

* The initial velocity of the truck is u_1 = 10 m/s.

* The initial velocity of the parked car is u_2 = 0 m/s.

* The final velocity of the car is v_2 = 15 m/s.

Solution:

According to the law of conservation of momentum, the net momentum of the system before and after the collision is the same.

Thus,

`m_1u_1+m_2u_2=m_1v_1+m_2v_2`

Substituting the known values,

`\begin{gathered} 3000*10+1000*0=3000v_1+1000*15 \\ 30000+0=3000v_1+15000 \\ 3000v_1=30000-15000 \\ 3000v_1=15000 \end{gathered}`

By simplifying,

`\begin{gathered} v_1=(15000)/(3000) \\ v_1=5\text{ m/s} \end{gathered}`

Thus, the velocity of the truck is 5 meters per second.