The given expression is-

We have to find three solutions for this expression. First, we use the zero property to find the first solution.

Where,

Now, we solve the quadratic equation to find the other two solutions.-

We have to find the two solutions using the quadratic formula-
![x_(1,2)=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/li72dimqx1poek8bdg3bs589861h83kfxl.png)
Where a=1, b=5, and c=-4.
Using the given information, we have
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