Given a quadrilateral ABCD with vertices
A(0,0)
B(5,0)
C(5,3)
D(0,3)
The quadrilateral is as shown below:
When dilated with a scale factor of 2 at the origin, the coordinates of the vertices are multiplied by 2 to get a new image.
Thus, we have
![\begin{gathered} A(0,0)\Rightarrow A^(\prime)(0,0) \\ B(5,0)\Rightarrow B^(\prime)(10,0) \\ C(5,3)\Rightarrow C^(\prime)(10,6) \\ D(0,3)\Rightarrow D^(\prime)(0,6) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qku6is5v7h8ko1iqg34dqe0xr5elfqwg4k.png)
Thus, the coordinates of the image of vertex C is (10,6)