Question

It take you 11.3 minutes to walk an average velocity of 1.2 m/s to the north from the bus stop to the museum entrance what is your displacement

Answer 1

813.6 m

Step-by-step explanation

The average velocity is:

`v_{\text{avg}}=(\Delta x)/(\Delta t)`

Where Δx is the displacement.

In this problem we have vavg = 1.2 m/s and time 11.3min. First we have to convert the time from minutes to seconds, for the units to be consistent with the velocity's units:

`\begin{gathered} 1\min =60s \\ \Delta t=11.3\min \cdot(60s)/(1\min )=678s \end{gathered}`

Now, solving the equation above for Δx :

`\Delta x=v_{\text{avg}}\cdot\Delta t`

And replacing the values:

`\Delta x=1.2(m)/(s)\cdot678s=813.6m`

We found that the displacement is 813.6 meters