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Find three consecutive odd numbers whose sum is 117

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4 votes

Answer:

37, 39 and 41

Step-by-step explanation:

Let the first odd number = x

The next two consecutive odd numbers are x+2 and x+4.

Taking the sum


\begin{gathered} x+x+2+x+4=117 \\ 3x+6=117 \\ 3x=117-6 \\ 3x=111 \\ x=(111)/(3) \\ x=37 \end{gathered}

The three consecutive odd numbers are 37, 39 and 41.

User Doris Liu
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