Question

Please solve this problem using the foil method

`{x}^(2) - 9`
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Answer 1

we know:
`a^2-b^2=(a+b)(a-b)`

So:
`x^(2) -9=x^(2) -3^2=(x+3)(x-3)`

Ok done. Thank to me :>

Answer 2

This is already in its simplest form, but if you set the equation equal to zero, it's (x-3)(x+3).

Explanation:

x^2-9=0

a= 1

b=0

c=-9

Factors of c (-9) that add up to make b (0): -3, 3

(x-3)(x+3)