Given:
The cyclist starts from A and reaches F.
The whole trip takes time,

To find:
c) The average speed
d) The average velocity
Step-by-step explanation:
c) The average speed is,

The total distance is,

The average speed is,

Hence, the average speed is 4 m/s.
d)
The average velocity is,

The displacement is,

The average velocity is,

Hence, the average velocity is 1.33 m/s.