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One number is 9 more than another number. if the sum of the numbers is 65, find both numbers

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Let x and y are the two unknown numbers.

One number is 9 more than another number


x=y+9\quad eq.1

The sum of the numbers is 65


x+y=65\quad eq.2

Substitute eq.1 into eq.2


\begin{gathered} x+y=65 \\ (y+9)+y=65 \\ y+9+y=65 \\ 2y+9=65 \\ 2y=65-9 \\ 2y=56 \\ y=(56)/(2) \\ y=28 \end{gathered}

So, the value of y is 28


\begin{gathered} x=y+9 \\ x=28+9 \\ x=37 \end{gathered}

Therefore, the two numbers are


\begin{gathered} x=37 \\ y=28 \end{gathered}

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