A standard deck consists of 52 cards, and 4 of them are four. Our exercise is about probability without replacement.
![P(4,4)=(4)/(52)\cdot(3)/(51)=(12)/(2562)](https://img.qammunity.org/2023/formulas/mathematics/college/xexaw1i0htjv9ajp9dacru4wv8bjtm5h3b.png)
This is the fraction form of the probability, but we want the percentage form. To convert 12/2562 to the percentage form, we only need to multiply by 100:
![P(4,4)=(12)/(2562)\cdot100(\text{\%})\approx0.45\text{\%}\approx0.5\text{\%}](https://img.qammunity.org/2023/formulas/mathematics/college/uuqyqr5fvthqgm329mm61b1hyvl6aht369.png)
Comment 1: We round 0.45 to 0.5 because the second decimal place 5 is equal to 5 (this is a general rule).
Comment 2: The formula for P(4,4) I used is this:
![P(4,4)=\text{ (probability of choosing a four in the first drawn)}\cdot\text{(Probability of drawing a four in the second drawn)}]()
If we pick a four up in the first drawn, we have thus 51 cards, and just three fours to choose among them in the second drawn.