First, let´s calculate the length of the sides of the triangle, by calculating the distance between the given points.
Use the following formula:
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/be685jmxw05hm2tq94m5iuge2xjynn1hfn.png)
where (x1,y1) and (x2,y2) are the limits of a segment with length d.
Then, the ditance between points X and Y is;
![d_(XY)=\sqrt[]{(-5-2)^2+(-4-(-1))^2}=\sqrt[]{49+9}=\sqrt[]{58}](https://img.qammunity.org/2023/formulas/mathematics/high-school/rvjp1a12hldmlpec3htsng1fl0p158xw6b.png)
The distance between points Y and Z is:
![d_(YZ)=\sqrt[]{(-2-(-5))^2+(3-(-4))^2}=\sqrt[]{9+49}=\sqrt[]{58}](https://img.qammunity.org/2023/formulas/mathematics/high-school/to9wygcparsz8sr3xf4i5d4j79vhoi8rbs.png)
and the distance between points Z and X is:
![d_(ZX)=\sqrt[]{(2-(-2))^2+(-1-3)^2}=\sqrt[]{16+16}=\sqrt[]{32}](https://img.qammunity.org/2023/formulas/mathematics/high-school/y2uaw2r6symqngynjx3su3d8c0up0a1h0a.png)
Then, you have two sides with the same length, which are sides XY and YZ and another side with a different length.
When a triangle has two sides with the same length, such a triangle is isosceles.