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Factor each expression completely:y^4(3y - 2) - 16(3y - 2)

User Fabio Phms
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1 Answer

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We the following:


y^4\left(3y-2\right)-16\left(3y-2\right)

solving:


\begin{gathered} y^4\left(3y-2\right)-16\left(3y-2\right) \\ 3y^5-2y^4-48y+32 \end{gathered}

User Sotero
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