The equation is given as

Before we begin solving, we need to expand the equation:

We can solve the equation using the quadratic formula:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/rxvf73usjbbwyik14knxdemoz21vfz2ufc.png)
where

Substituting, we have
![\begin{gathered} u=\frac{-4\pm\sqrt[]{4^2-(4*1*-4)}}{2*1} \\ u=\frac{-4\pm\sqrt[]{32}}{2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/uzcilxodzab4lshx79f9kqowhmij6l1iaj.png)
Therefore, we can calculate the values of u to be
![\begin{gathered} u=\frac{-4+\sqrt[]{32}}{2} \\ u=-2+2\sqrt[]{2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/p6a8c3xdqnv8lfwrwndyx1ev1w89ag2h4q.png)
or
![\begin{gathered} u=\frac{-4-\sqrt[]{32}}{2} \\ u=-2-2\sqrt[]{2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vd9rxbmj7b5499aapifwpolzrapyv78kly.png)
Therefore, the roots are given as
![u=\mleft\lbrace-2+2\sqrt[]{2},-2-2\sqrt[]{2}\mright\rbrace](https://img.qammunity.org/2023/formulas/mathematics/college/jq9ng0t42b77zoewe1lh1ejl3fkqq1bx26.png)