Question

How does h(x) = 8+ change over the interval from x = 8 to x = 9?

Answer 1

We have the function:

`h(x)=8^x`

We have to find how h(x) change over the interval from x = 8 to x = 9.

We can find this as:

`(h(9)-h(8))/(h(8))=(h(9))/(h(8))-1=(8^9)/(8^8)-1=8^(9-1)-1=8-1=7`

The value of h(9) is 8 times the value of h(8), so this is an increase of 7 times the value of h(8). This can be expressed as "h(x) increases by 700%".

Answer: h(x) increasees by 700%.