Question

[H+] = 2.5 x 10-3M find the pH and pOH

Answer 1

pH = 2.6

pOH = 11.4

Explanations:

The formula for calculating the pH of a solution is given as;

`pH=-log[H^+]`

Given the following parameter

`[H^+]=2.5*10^(-3)`

Substitute the given parameter into the formula

`\begin{gathered} pH=-log(2.5*10^(-3)) \\ pH=-log(0.0025) \\ pH=-(-2.6) \\ pH=2.6 \end{gathered}`

Determine the pOH of the solution

`\begin{gathered} pH+pOH=14 \\ pOH=14-pH \\ pOH=14-2.6 \\ pOH=11.4 \end{gathered}`

Therefore the pH and pOH of the solutionare 2.6 and 11.4 respectively