A committee must be formed with 3 teachers and 4 students. If there are 8 teachers to choose from, and 16 students, how many different ways could the committee be made?

Question

asked Feb 20, 2023 184k views

1 Answer

Nrkn · Answer 1 · 2023-02-25T17:59:33+0000

Answer:

$\text{ Total number of ways=}101920$

Explanation:

To calculate the different ways of this combination:

*3 teachers from 8 teachers

*4 students from 16 students

Then,

$(16!)/((16-4)!*4!)*(8!)/((8-3)!*3!)=Total\text{ number fo ways}$

Solve.

$\begin{gathered} \text{ Total number of ways=}1820\cdot56 \\ \text{ Total number of ways=}101920 \end{gathered}$