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A committee must be formed with 3 teachers and 4 students. If there are 8 teachers to choose from, and 16 students, how many different ways could the committee be made?

User Zotty
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1 Answer

2 votes

Answer:


\text{ Total number of ways=}101920

Explanation:

To calculate the different ways of this combination:

*3 teachers from 8 teachers

*4 students from 16 students

Then,


(16!)/((16-4)!*4!)*(8!)/((8-3)!*3!)=Total\text{ number fo ways}

Solve.


\begin{gathered} \text{ Total number of ways=}1820\cdot56 \\ \text{ Total number of ways=}101920 \end{gathered}

User Nrkn
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