Question

Give the equation of the line in slope intercept form that goes through the points

Answer 1

1. Use the next formula to find the slope:

`m=(y_2-y_1)/(x_2-x_1)`
`m=(-4-3)/(6-(-5))=(-7)/(6+5)=-(7)/(11)`

Slope: m= -7/11

2. Use one of the points and the slope to find the y-intercept (b):

`\begin{gathered} y=mx+b \\ \\ (-5,3) \\ y=3 \\ x=-5 \\ m=-(7)/(11) \\ \\ 3=-(7)/(11)(-5)+b \\ 3=(35)/(11)+b \\ \\ 3-(35)/(11)=b \\ \\ (33-35)/(11)=b \\ \\ -(2)/(11)=b \end{gathered}`

3. Use the slope and y-intercept t write the equation in slope-intercept form:

`\begin{gathered} y=mx+b \\ \\ y=-(7)/(11)x-(2)/(11) \end{gathered}`Then, the equation of the line is: y= -7x/11 - 2/11