We have to find the angle at vertex J.
We know the shortest arc JK and the shortest arc JL.
As a property of the arcs, the inscribed angle
We can apply the same property to angle K:
![m\angle K=(1)/(2)\text{arc JL}=(1)/(2)\cdot94\degree=47\degree](https://img.qammunity.org/2023/formulas/mathematics/college/y2g3s8tvk443m1mcp5bkresriv9wq660x5.png)
Now we have two angles of the triangle. We know that the sum of the measures of the interior angles of a triangle is equal to 180°, so we can write:
![\begin{gathered} m\angle J+m\angle L+m\angle K=180\degree \\ m\angle J+63+47=180 \\ m\angle J=180-63-47 \\ m\angle J=70\degree \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x9nvl1d0dq282rrp37kyqu3xbo7tiglp3x.png)
Answer: The angle at vertex J is 70 degrees.
NOTE: we could have solve it applying the relation between inscribed angles and arcs with angle J as:
![m\angle J=(1)/(2)\text{arc LK}=(1)/(2)(360-94-126)=(1)/(2)\cdot140=70\degree](https://img.qammunity.org/2023/formulas/mathematics/college/r612to3nmb6bj0z075gfvsp3dtpcp2hmr1.png)
The arc LK is the full circle, 360°, less the other arcs, 94° and 126°.