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Solve for y in the first equationx-3y=-62x-7y=10

1 Answer

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The first equation is


x-3y=-6

First, we subtract x from each side.


\begin{gathered} x-x-3y=-6-x \\ -3y=-6-x \end{gathered}

Then, we divide the equation by -3.


\begin{gathered} -(3y)/(-3)=(-6-x)/(-3) \\ y=2+(x)/(3) \end{gathered}

Hence, the answer is


y=2+(x)/(3)

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