The compound interest formula is given by
![A=P(1+(r)/(n))^(n* t)](https://img.qammunity.org/2023/formulas/mathematics/college/wxmh4ufolyninwpqvbx5aizfice4tg8myf.png)
where A is the resulting amount after t years, P is the present value (or principal amount) , r is the annual interest rate and n is the number of compounding periods per year.
From the given information, we have that
![\begin{gathered} P=1000 \\ r=0.04 \\ n=4\text{ (quaterly=4 times per year)} \\ t=12\text{ years} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/k2fl91i01qk8m8coqqzsx1g55oeq4l4l1y.png)
By substituting these values into the formula, we have
![A=1000(1+(0.04)/(4))^(4*12)](https://img.qammunity.org/2023/formulas/mathematics/college/73g1g6daj0jep7phv8xldtn3k1nnwfv837.png)
which gives
![\begin{gathered} A=1000(1.01)^(48) \\ A=1000(1.6122) \\ A=1612.226 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/iao90i8iar0qkzsije2n42u0iizb2kmxn3.png)
Therefore, by rounding to the nearest thousandth, the answer is $1612.23, which corresponds to the last option.