We have to find the equation of a line that pass through the point (-3,5) and is parallel to the line 25x+3y=15.
All parallel lines to 25x+3y=15 can be written as:
![25x+3y=C](https://img.qammunity.org/2023/formulas/mathematics/college/zw5xrntmzhmz1itsj7gvp1pmqb21x5q53g.png)
where C is a constant that allows us to change the position of the line to fit any point.
As the point (-3,5) belongs to the line we are looking for, it has to satisfy the equation. So we can write:
![\begin{gathered} 25x+3y=C \\ 25(-3)+3(5)=C \\ -75+15=C \\ C=-60 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2vqvzeoa7559pmis5p6dymrylnzxvc5iik.png)
With the value of C defined, we can write the equation of the line as:
![25x+3y=-60](https://img.qammunity.org/2023/formulas/mathematics/college/yvl895tbzno6ay64ohyjgemip5cxl8klbu.png)
Answer: 25x+3y=-60