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3(y + 1) + 2y = 5( y - 1 ) + 5

User Shalene
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1 Answer

4 votes

Answer:

There are no values for y that make this equation true.

Explanation:

Distribute the 3 and 5 to their respective parenthesized quantities:


3y+3+2y=5y-5+5

Simplify:


5y+3=5y

Subtract 5y from both sides:


3=0

Note that 3 cannot equal zero, therefore this equation has no values for y which make it true.

User Udo
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