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Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (-3,5) and parallel to x + 2y = 5.

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we need to find the equation of a like, in two different ways

a) slope-interceppt Y=mX+b

b) standard form aX+bY=c

the information we have is,

it's parallel to x+2y=5 (this mean the have the same slope

so, let's find it

x+2y=5

2y=5-x

y=5/2 - 1/2 x

the slope is m= -1/2

The other thing we know is the line passing through (-3,5)

so when x=-3 the value of Y has to be 5

So let's check, until now we have the slope, our line is y= -1/2x + B

let's find out the value of B, replacing the values of x and y

5= -1/2 * -3 +B

5= 3/2 + B

7/2= B

So, the answer to (a) is=

Y= -1/2 X + 7/2

b) we need to change from slope to standard form

Y= -1/2 X + 7/2

Y + 1/2 X= 7/2

i think that's standard form, but also you can divide for 7/2 to get

2/7 Y + 1/7 X = 1

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