A 9-sided die has 9 sides meaning that there are a total of 9 possible outcomes.
We are interested in the outcomes "7" OR a "8"
The probability that the number rolled is a "7" is given by
![P=\frac{number\text{ of favorable outcomes}}{\text{total number of outcomes}}](https://img.qammunity.org/2023/formulas/physics/high-school/5iowztnthzm82qx0vtwmtqmqtarswb24cn.png)
There is only 1 favorable outcome which is to roll a "7" and the total number of outcomes are 9.
![P(7)=(1)/(9)](https://img.qammunity.org/2023/formulas/physics/high-school/t4k7kmklhlka1e9fv8t3j9vr1ppkmy3sd2.png)
So, the probability that the number rolled is a "7" is 1/9
The probability that the number rolled is a "8" is given by
There is only 1 favorable outcome which is to roll a "8" and the total number of outcomes are 9.
![P(8)=(1)/(9)](https://img.qammunity.org/2023/formulas/physics/high-school/juhh8xjgh7scdgf5ikqrq9p2z4adxch1cl.png)
So, the probability that the number rolled is a "8" is 1/9
The probability that the number rolled is a "7" OR a "8" is given by
![P(7\; or\; 8)=P(7)+P(8)=(1)/(9)+(1)/(9)=(2)/(9)](https://img.qammunity.org/2023/formulas/physics/high-school/wfcygq85glw06pqqh01bojc2ul23q1n4iv.png)
There is a 2/9 probability that the number rolled is a "7" OR a "8".