Question

Hi, can you help me to solve this problem, please!!!

Answer 1

Given:

The equation of a parabola is given as,

`y=x^2-5`

The objective is to find the axis of symmetry of the parabola.

Step-by-step explanation:

The general formula to find the axis of symmetry of a parabolic equation is,

`x=-(b)/(2a)\text{ .. . . . . (1)}`

From the given equation,

`\begin{gathered} a=1 \\ b=0 \\ c=-5 \end{gathered}`

On plugging the obtained values in equation (1),

`\begin{gathered} x=-(0)/(2(1)) \\ x=0 \end{gathered}`

Hence, the axis of symmetry of the parabola is at x = 0.