Question

Find the area of a trapezoid whose height is 7 in in whose bases are 14 in in 10 inches

Answer 1

The area of a trapezoid is the average of the bases multiplied by the height

`\begin{gathered} A=(a+b)/(2)\cdot h \\ \text{Where} \\ a\colon\text{ long base} \\ b\colon\text{ short base} \\ h\colon\text{ height} \end{gathered}`

So, in this case, you have

`\begin{gathered} a=14\text{ in} \\ b=10\text{ in} \\ h=7\text{ in} \end{gathered}`
`\begin{gathered} A=(a+b)/(2)\cdot h \\ A=(14in+10in)/(2)\cdot7\text{ in} \\ A=84\text{ square inches} \end{gathered}`

Therefore, the area of a trapezoid w