The compound interest formula is given by the formula

Where A = Amount after t years
r = rate = 6
t = time = 5
p = $ 25000
For the first year

For the second year
P=26500+25000=51500

For the third year
P=54590 + 25000=79590

For the fourth year
P=84365.4 + 25000=109365.4

For the fifth year
P= 115927.324 + 25000 =140927.324

At the start of the 6th year
P= 149382.962+25000= 174382.96
Answer = $174382.96
Option B is correct