2cosAcosB = • cos(A + B) + cos(A - B) • sin(A - B) + tan(A + B)

Ryan Weiss asked Apr 18, 2022

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5 votes

2cosAcosB =

• cos(A + B) + cos(A - B)
• sin(A - B) + tan(A + B)

Ryan Weiss asked Apr 18, 2022

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8 votes

Answer:

2cosAcosB = cos( A + B ) + cos( A - B )

Kludge answered Apr 24, 2022

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