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a sample of 48 g of diatomic oxygen gas occupies an unknown volume at a pressure of 12.3 atm and a temperature of 7.60 degrees celsius. Find the volume of this sample of O2

User ISaumya
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In order to find the volume of this sample, we need to use the Ideal Gas Law formula, which is:

PV = nRT

We have:

P = 12.3 atm

V = ?

n = this number of moles we will have to find before using the formula

R = this is the gas constant, 0.082

T = 7.6°C, but we need it in Kelvin, 280.75 K

To find the number of moles we will use the given mass, and the molar mass of O2, which is 16g/mol

16g = 1 mol

48g = x moles

x = 3 moles of O2 in 48g

Now we add these values into the formula

12.3 * V = 3 * 0.082 * 280.75

12.3V = 60.0645

V = 5.6 Liters is the volume

User Sgt B
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