Question

C. Let m5 = 63º. M 5 6 78 mZ1 = mZ2 = m23 = m24 = m26 = m27= m28 = D. Let m27 = 123°. mZ1 = mZ2 = m23 = m24 = m25 = m26 = mZ8 = 1 2

Answer 1

You have two parallel lines crossed by a secant line. Based on the congruency of the angles, you have:

m∠1 = m∠5 = 63°

m∠2 = 180 - 63 = 117°

m∠3 = m∠2 = 117°

m∠4 = m∠1 = 63°

m∠5 = 63°

m∠6 = m∠2 = 117°

m∠7 = m∠5 = 63°

m∠8 = m∠6 = 117°