Question

I inserted a picture of question 12graph the solution to the inequality.

Answer 1

Let's first determine the solution of the given inequality,

`\text{ x}^2\text{ }<\text{ }16`

We get,

`\text{ x}^2\text{ }<\text{ }16`
`\text{ }\sqrt{\text{x}^2}\text{ }<\text{ }√(16)`
`\text{ x }<\text{ }\pm\text{4}`

Since +4 is the highest, we will be starting the mark at +4, because it will still include all numbers less than -4.

Graphing this in a number line will be,