To find the median, first, we have to order the scores. The ordered list of scores is:
62,66, 70, 72, 73, 76, 77, 85, 85, 88, 90, 92, 93, 98, 100, 100
Given that there are 16 scores, the median (which is placed at the half of the ordered list) is placed between the 8th and 9th scores (the average between them).
8th score: 85
9th score: 85
median = (85 + 85)/2
median = 85
The mean is computed as follows:
![\operatorname{mean}=\frac{\text{ sum of the terms}}{\text{ number of terms}}]()
In this case, the number of terms is 16. Therefore, the mean is:
![\begin{gathered} \operatorname{mean}=(62+66+70+72+73+76+77+85+85+88+90+92+93+98+100+100)/(16) \\ \operatorname{mean}=(1327)/(16) \\ \operatorname{mean}\approx83 \end{gathered}]()
Given that there are no outliers in the data set, the mean can be used as a measure of the center of a data set.