Hello!
We have the equation below:
![-3x^3-18x^2-24x](https://img.qammunity.org/2023/formulas/mathematics/college/nicblsaj0a72vndc2idqbk1n4m3iffmi4i.png)
First of all, note that in all terms we have multiples of -3x. So, let's put it in evidence:
![-3x\cdot(x^2+6x+8)](https://img.qammunity.org/2023/formulas/mathematics/college/rug6fzh1h0uqm5v4g6l1o0isfsudijv5iy.png)
Now, let's rewrite 6x as 4x+2x:
![-3x\cdot(x^2+4x+2x+8)](https://img.qammunity.org/2023/formulas/mathematics/college/884n1nimr9n0gw339laarpx84rjrc0cf97.png)
Note that we can put x in evidence because of the first and second terms, and 2 in evidence because of the third and fourth terms. Look:
![-3x\cdot(x^\cdot(x+4)+2(x+4))](https://img.qammunity.org/2023/formulas/mathematics/college/y19wdgtyvy1whu63z2ryygunb34hkmlu4q.png)
As we have (x+4) twice, let's put it in evidence too:
![-3x\cdot(x+4)\cdot(x+2)](https://img.qammunity.org/2023/formulas/mathematics/college/6q78knj8wtic0l364cu04174s3zhebmwha.png)
Answer:
Alternative B. -3x(x+2)(x+4)