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9 votes
Calculate the HCF of 8a³-27, 4a²-9 and 4a²-12a+9​

User Eman Fateen
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1 Answer

8 votes
8 votes


\: \: \: \: \:

first add

(3a²-5a+5)+(a³-5a²+8)

=3a²-5a+5+a³-5a²+8

=a³-2a3a²-5a²+5+8

=a³-2a²+13

and now,

substract a³-2a²+13 from a²-4a²-9

=7a²-4a²-9-(a³+13)

=7a²-4a²-9-a³+2a²-13

= a³+7a²-4a²+2a²-9-13

=-a³+5a²-22

hope it helps

User Jourdan
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