Answer:
![(3)/(7)](https://img.qammunity.org/2023/formulas/mathematics/high-school/cg2l69rtxrkru1ebc3ndef9q5gm7v09sbd.png)
Explanation:
Start by finding how many integers there are from 10-30...
30-10+1=20+1=21
Note we have to add 1 since it is inclusive.
Now, let's find how many multiples of 4 or 5 there are from 10-30...
4*3=12
4*4=16
4*5=20
4*6=24
4*7=28
5*2=10
5*3=15
5*4=20
5*5=25
5*6=30
5+5-1=9
Note we have to subtract 1 since 20 is counted twice.
The probability would be...
![(Multiples\ of\ four\ and\ five\ from\ 10-30)/(Amount\ of\ integers\ between\ 10-30)=(9)/(21)=(3)/(7)](https://img.qammunity.org/2023/formulas/mathematics/high-school/88hwa44m0llmz3rpvbvn1dm3dszar2jn8s.png)