From the question
For two supplementry angles
One angle is 5 degree less than 4 times the othe angle
Let one of the angle be x
Then the other angle will be 4x - 5
Hence by supplementary angles
![x+4x-5=180](https://img.qammunity.org/2023/formulas/mathematics/college/e1oxvr6150y4tgbko8qhmibqne1rts28lz.png)
solving for x
![\begin{gathered} 5x-5=180 \\ 5x=180+5 \\ 5x=185 \\ x=(185)/(5) \\ x=37 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/s6ldadw56ab75fhfg3zoo10i9s9r6mjlx2.png)
Therefore
One of the angle is 37 degrees
The other angle is
![\begin{gathered} 4x-5=4(37)-5 \\ =148-5 \\ =143 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gn68537wiqjs8dkzal6a8kcy85d20epefl.png)
Therefore the supplementary angles are 37 degrees and 143 degrees