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Rpranata · Answer 1 · 2023-08-18T13:16:39+0000

We have to calculate the area of a triangle with height h = √343 cm and base b = √28 cm.

We can use the formula:

$\begin{gathered} A=(1)/(2)bh \\ A=(1)/(2)\sqrt[]{28}\cdot\sqrt[]{343} \\ A=(1)/(2)\sqrt[]{28\cdot343} \\ A=(1)/(2)\sqrt[]{9604} \\ A=(1)/(2)\sqrt[]{4\cdot49\cdot49} \\ A=(1)/(2)\sqrt[]{4}\cdot\sqrt[]{49}^2 \\ A=(1)/(2)\cdot2\cdot49 \\ A=49\operatorname{cm}^2 \end{gathered}$

Answer: the are of the triangle is 49 cm²

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