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4x^2-4x-48needs to be factored

User Geoff Cox
by
7.8k points

2 Answers

4 votes

Answer: v^4x^2−4x−48=0

Step-by-step explanation:

User Sergey Khalitov
by
7.9k points
4 votes

Answer:


4\left(x^2-x-12\right)

Step-by-step explanation:

We are given the expression:


4x^2-4x-48

We will proceed to factor as shown below:


\begin{gathered} \text{Each of the term is divisible by ''4''. That makes ''4'' the highest common factor. We have:} \\ 4\left(x^2-x-12\right) \\ \\ \therefore4\left(x^2-x-12\right) \end{gathered}

User John Martin
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8.1k points

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