Question

3. A parallel-plate capacitor has a charge of 8.6 uc when charged by a potential difference of 3.5 V. What is its capacitance? * (3 Points) 25 x 10-60

Answer 1

The charge in a capacitor is given by:

`Q=CV`

Plugging the values of the charge anf the potential differnce and solving for the capacitance we have:

`\begin{gathered} 8.6*10^(-6)=3.5C \\ C=(8.6*10^(-6))/(3.5) \\ C=2.5*10^(-6) \end{gathered}`

Therefore the capacitance is:

`2.5*10^(-6)\text{ F}`