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The Keck Telescope has a diameterof 10.0 m. When it is looking atMars, 7.38 1010 m from us, how farapart are the closest objects it couldpossibly resolve? Assume the lighthas wavelength 633 nm.[?] m

User Yiyi You
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1 Answer

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Given:

Diameter, D = 10.0 m

Distance, x = 7.38 x 10¹⁰ m

Wavelength, λ = 633 nm

Let's find how far apart the closest objects it could possibly resolve.

First, apply the formula for the angle for angle separation (limit of resolution):


\theta=(1.22\lambda)/(D)

Thus, we have:


\begin{gathered} \theta=(1.22*633*10^(-9))/(10.0) \\ \\ \theta=\frac{7.7226\operatorname{*}10^(-7)}{10.0} \\ \\ \theta=7.7226\operatorname{*}10^(-8)\text{ rad} \end{gathered}

Now, to find the distance of the closest objects, we have:


d=\theta *x

Thus, we have:


\begin{gathered} d=7.7226*10^(-8)*7.38*10^(10) \\ \\ d=5699.28\text{ m} \end{gathered}

Therefore, the distance of the closest objects is 5699.28 meters.

• ANSWER:

5699.28 m

User Mshwf
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