Question

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Find the roots of the equation x2 – 3x – m (m + 3) = 0, where m is a constant.​


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Answer 1

Answer:-m or m+3

Explanation:

`x^(2) -3x -(m^(2)+3m) =0\\\\x^(2) -3x -m^(2) -3m=0\\`

`x^(2) -m^(2) -3x - 3m=0`

Applying difference of two squares

⇒(
`x^(2) -m^(2)`)=(x+m)(x-m)

Substituting this for (
`x^(2) -m^(2)`)

Factorising -3x-3m=-3(x+m)

(x+m)(x-m)-3(x+m)=0

since we have double (x+m),we'll pick one

⇒(x+m)=0

or (x-m-3)=0

⇒x=-m or x= m+3